In Q&A bank part 2, for the solution of question 2.6 (Iii), how is variance of ( x (bar) | theta ) = (1/n) * var( Xj| theta)
\(var(\bar X) = var(\sum X_j /n) = \frac{1}{n^2} \sum var(X_j) \) since independent \(=\frac{1}{n^2} n var(X_j)\) since identical