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Qu 3.15

S

Sharon

Member
Can anyone explain the solution to qu 3.15 to me? I understand that q[x]+1 > q[x+1] and q[x+2]+2 > q[x+4] but I don't understand why the difference between the second pair is less than the first.
 
i dunno

Sharon said:
Can anyone explain the solution to qu 3.15 to me? I understand that q[x]+1 > q[x+1] and q[x+2]+2 > q[x+4] but I don't understand why the difference between the second pair is less than the first.
Click to expand...

let me try my hand at this one. say we got q[x+s]+s, now this lies somewhere between (qx+2s,...,q[x+2s]),
now as s->big number:
q[x+s]+s ->qx+2s i.e it moves towards the left limit
q[x+2s]->q[x+2s] i.e. it stays at the lower limit
but then the difference gets bigger!,
hmm maybe i should just change the question, cause i dont want to change my answer
looking at q[x+s]+s<q[x]+2s then the difference gets smaller..

i know i am wrong, because 'the book' is infallible. we may have to use non logical enlightened reasoning, any rousseaux's out there?
 
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